32^1/5X2^x-3/4^x+1=2

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Solution for 32^1/5X2^x-3/4^x+1=2 equation: 



32^1/5X^2^X-3/4^X+1=2

We move all terms to the left:

32^1/5X^2^X-3/4^X+1-(2)=0



Domain of the equation: 5X^2^X!=0

X!=0/1

X!=0

X∈R





Domain of the equation: 4^X!=0

X!=0/1

X!=0

X∈R



We add all the numbers together, and all the variables

32^1/5X^2^X-3/4^X-1=0

We calculate fractions

We do not support eXpression: X^3

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